(2x^2-3x-1)^2-3(2x^2-3x-5)-16=0

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Solution for (2x^2-3x-1)^2-3(2x^2-3x-5)-16=0 equation: 



(2x^2-3x-1)^2-3(2x^2-3x-5)-16=0

We multiply parentheses

-6x^2+(2x^2-3x-1)^2+9x+15-16=0

We add all the numbers together, and all the variables

-6x^2+9x+(2x^2-3x-1)^2-1=0

We move all terms containing x to the left, all other terms to the right

-6x^2+9x+(2x^2-3x-1)^2=1

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